3(x-8) + 7= 2X 3X-24+7= 2X (distribute 3 within the parentheses) -17= 2X-3X (Here I combined two steps. -24+7=-17 and I moved 3X to the other side. Technically I subtracted 3X from both sides. -17=-X (subtract 2X-3X) X=17 (X is not allowed to be positive, so remove the - sign from both sides)

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Let's see if this is true. Assume that their sum is 48. So, x + (x +1) + (x + 2) = 48 3x + 3 = 48 Subtract 3 at both sides; 3x = 45 Divide 3 to both sides; x = 15 x + 1 = 15 + 1 = 16 x + 2 = 15 + 2 = 17 So, 15 + 16 + 17 = 48 Answer: The sum of three consecutive integers such as 15, 16, and 17 is 48.

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It is x^3 - x^2 + 5x - 1Further Information:-Dividend: 4x^4 -x^3 +17^2 +11x +4Divisor: 4x +3Quotient: x^3 -x^2 +5x -1Remainder: 7