NTN Insert Brg (Standard) (F-UC205-100D1) - ntn f ntn
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There is however a problem with your solution. In your use of the Law of Sines you have 1500/sin(70). But the side of length 1500 m is not opposite the angle at B.
I constructed a triangle with points A,B, and C. I tried to use the Law of Sines to find Angle C. I did 1500/sin70 = 1000/sin C to find C to be equal to 38.7 degrees. With this knowledge, angle B must equal 71.2 degrees. Using the Law of Sines again where side b/sin71.2 = 1000/sin38.8, and I found side b to equal 1514.(Side b being the distance from C to A). Would the bearing from C to A therefore be S 71.2 E? Thanks.
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Here you can see an overview of the commodity codes used in this sub-division. The first six digits refer to the classification in the WCO Harmonized System (HS). This classification is further subdivided by the European Union into the eight-digit Combined Nomenclature (CN) codes. For import declarations, these codes are subdivided further into ten-digit Taric codes. For import and export customs declarations, commodities need to be classified in the Combined Nomenclature. When classifying a product, you need to check a lot of different data sources. You can find them all in our online platform, just one mouse click away.
I'm not sure which angle of the implied triangle to use for the bearing and which directions to give(North,South,East, or West)
We provide customs information for the UK, Switzerland and the EU, as well as national trade tariff information for many EU member stated, such as Belgium, the Netherlands, Sweden, Germany and Italy.
I drew a diagram of the triangle you described and added a North-South line at C. I agree that the bearing from C to A is S 71.2o E. There is a good explanation of bearings at a page kept by David Levesen, a faculty member in the Department of Geology at Brooklyn College, City Uiversity of New York.
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